2x^2/3-5x^1/3-42=0

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Solution for 2x^2/3-5x^1/3-42=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-((5*x^1)/3)-42 = 0

(2*x^2)/3+(-5/3)*x-42 = 0

2/3*x^2-5/3*x-42 = 0

DELTA = (-5/3)^2-(-42*2/3*4)

DELTA = 1033/9

DELTA > 0

x = ((1033/9)^(1/2)+5/3)/(2/3*2) or x = (5/3-(1033/9)^(1/2))/(2/3*2)

x = 3/4*((1033/9)^(1/2)+5/3) or x = 3/4*(5/3-(1033/9)^(1/2))

x in { 3/4*(5/3-(1033/9)^(1/2)), 3/4*((1033/9)^(1/2)+5/3) }

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